Alfred is a populated place located in Allegany County, New York. It appears on the Alfred USGS 7.5-minute topographic quadrangle. The elevation at this location is approximately 1,765.09 feet (538.00 m) above sea level.
Allegany County · New York
Alfred is a populated place located in Allegany County, New York. It appears on the Alfred USGS 7.5-minute topographic quadrangle. The elevation at this location is approximately 1,765.09 feet (538.00 m) above sea level.