Seymour is a populated place located in Wayne County, Iowa. It appears on the Seymour East USGS 7.5-minute topographic quadrangle. The elevation at this location is approximately 1,059.71 feet (323.00 m) above sea level.
Wayne County · Iowa
Seymour is a populated place located in Wayne County, Iowa. It appears on the Seymour East USGS 7.5-minute topographic quadrangle. The elevation at this location is approximately 1,059.71 feet (323.00 m) above sea level.